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Tim Lewis
Joined: 29 Sep 2001 Posts: 794 Location: Afghanistan, The land of POPPIES!!!,
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Posted: Sun Feb 22, 2004 2:23 pm Post subject: |
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| I think breakfast is just a marketing ploy by the cereal companies. I don't think anyone really needs to eat in the morning. After all, what have you been doing all night? Sleeping, right? You shouldn't need to eat after that. Lunch makes sense, you've been working for a few hours. Same thing with dinner. Breakfast, though, that's just a fallacy. |
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Pete Muller Moderator
Joined: 23 Jul 2001 Posts: 1950 Location: United States, California,
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Posted: Sun Feb 22, 2004 2:27 pm Post subject: |
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In other words, the kinetic energy of a rolling body is equal to the sum of translational and rotating components.
Arrrghh! Finally!!!
Thanks Joseph!
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Larry Hayashigawa
Joined: 21 Oct 2001 Posts: 399 Location: United States, California,
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Posted: Sun Feb 22, 2004 3:19 pm Post subject: |
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Bottom Line
The original post was questioning whether decreasing the rotational inertia improved acceleration. McFadden believes it does, from a theory standpoint he is wrong but from a practical perspective he is right. Acceleration does increase but it does not have nearly the effect that many believe it does.
Checking out of this thread
Larry |
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Mike Goebel
Joined: 28 Jul 2001 Posts: 5765 Location: United States, California, Winnetka
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Posted: Sun Feb 22, 2004 3:24 pm Post subject: |
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That was a sweet example Joseph
Mike MFG. |
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joseph hollinger
Joined: 12 Sep 2002 Posts: 9475 Location: United States, California, san francisco
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Posted: Sun Feb 22, 2004 3:59 pm Post subject: |
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| Mike Goebel wrote: | That was a sweet example Joseph
Mike MFG. |
Thanks, but it's pretty much straight out of the book. |
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joseph hollinger
Joined: 12 Sep 2002 Posts: 9475 Location: United States, California, san francisco
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Posted: Sun Feb 22, 2004 4:01 pm Post subject: |
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| Larry Hayashigawa wrote: | Bottom Line
The original post was questioning whether decreasing the rotational inertia improved acceleration. McFadden believes it does, from a theory standpoint he is wrong but from a practical perspective he is right. Acceleration does increase but it does not have nearly the effect that many believe it does.
Checking out of this thread
Larry |
I think that's absolutely true. Even though the effect is real, the amount
you can change things on a kart isn't detectable. |
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Mike Goebel
Joined: 28 Jul 2001 Posts: 5765 Location: United States, California, Winnetka
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Posted: Sun Feb 22, 2004 4:38 pm Post subject: |
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| joseph hollinger wrote: | | Mike Goebel wrote: | That was a sweet example Joseph
Mike MFG. |
Thanks, but it's pretty much straight out of the book. |
Still it used his instant center method of thinking and proved him wrong. And what is better that proving someone wrong ?
Mike G. |
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Charles Pou
Joined: 26 Aug 2001 Posts: 497 Location: United States, Texas, Dallas
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Posted: Sun Feb 22, 2004 4:58 pm Post subject: |
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I agree with Scott's premise, not because of physics, but because of economics.
The law of diminishing returns comes to mine. As a racing kart for example is developed, you pay more and more for less and less results. At some point you realize you are paying big $'s for very little, if any increase in speed.
For F1/ NASCAR where millions are at stake, cost is no object. Kart racing as a hobby is another matter....
As for Scott's physics, IMO it's flawed because it leaves out the energy to rotate the flywheel, it only accounts for the energy to move the flywheel down the track.
Continuing the example of 2 karts, each the same in all respects, except kart #1 has an extra 100# sitting in the seat and Kart #2 has a 100# flywheel mounted the rear axle. The flywheel is fitted with a niffty one way bearing (so as the kart moves forward the flywheel is rotated, but as the kart is slowed or stops the flywheel is allowed to freewheel).
Accelerate both karts over an equal distance and stop. Kart #2 should accelerate slower than kart #1, because it takes more energy to move 100# down the track and rotate it (as with kart #2), than to just move it down the track (as with kart #1).
When kart #2 comes to a stop, the 100# flywheel is still spinning and has significant energy that could be used, such as move the kart forward from a stop. On the other hand, the 100# weight in the seat of kart #1 has no such energy.
So where did the extra energy in the spinning flywheel come from? It came from the engine, same configuration both karts. Kart #1 used more of the available engine power to move the kart down the track so it should be faster.
Kart #2 wasted some of the available energy spinning the flywheel. In effect Kart #2 was less efficient using the available power for the intended purpose.
So, given the same amount of energy, the less you use to rotate moving parts, the more you have available to accelerate the kart down the track, and the faster you should be.
However, please don't get too carried away, or you may later realize you spent your retirement racing karts.  |
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Scott McFadden
Joined: 20 Jul 2001 Posts: 125
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Posted: Sun Feb 22, 2004 7:01 pm Post subject: |
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[quote="Larry Hayashigawa"]Bottom Line
The original post was questioning whether decreasing the rotational inertia improved acceleration. McFadden believes it does, from a theory standpoint he is wrong but from a practical perspective he is right. Acceleration does increase but it does not have nearly the effect that many believe it does.
Hold on there Larry that's not what I said at all. I said in short that as long as the total wieght of the kart is constant, reducing the rotational mass at the expence of ballast will make no difference to the kart's straight-line acceleration.
I was referring to the wheels brake rotors chains sprokets etc who's acceleration is 1:1 with the forward acceleration of the kart. The flywheel stuff was thrown in later and ads a degree of complication that you have addressed. But I would like to read your analysis of just the chasis rotating parts, disregarding engine parts for now. _________________ Scott |
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Scott McFadden
Joined: 20 Jul 2001 Posts: 125
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Posted: Sun Feb 22, 2004 7:08 pm Post subject: |
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[quote="Pete Muller"]In other words, the kinetic energy of a rolling body is equal to the sum of translational and rotating components.
so..... if you increase the translational component by the same amount you deacrease the rotational component (take wieght off the brake rotor and add it to the back of the seat) kinetic energy remains unchanged _________________ Scott |
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Pete Muller Moderator
Joined: 23 Jul 2001 Posts: 1950 Location: United States, California,
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Posted: Sun Feb 22, 2004 7:36 pm Post subject: |
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| Quote: | | so..... if you increase the translational component by the same amount you deacrease the rotational component (take wieght off the brake rotor and add it to the back of the seat) kinetic energy remains unchanged |
No!
The relationship between the two is not linear. It says: "the sum of the components"... not the "sum of the weights or masses". By "components", it is referring to the sum of the kinetic energy(s).
Think about what you just said! -- it makes no sense. You didn't give a radius of the center of mass at all. Are you assuming that removing one pound from the rear axle assembly at a 1" radius will act exactly the same as 1 pound at a 5" radius? That's what you're implying.
I think Joseph might need to explain this with some math... I "understand" the issue, but I can't easily give you the formula for the relationship. I'll leave that to someone that has a better education than I do.  _________________ Muller Machine
How-to pages, tech documents, & more
Ultra-precision machining/blueprinting for engine builders
Last edited by Pete Muller on Sun Feb 22, 2004 7:43 pm, edited 1 time in total |
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joseph hollinger
Joined: 12 Sep 2002 Posts: 9475 Location: United States, California, san francisco
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Posted: Sun Feb 22, 2004 7:42 pm Post subject: |
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| Pete Muller wrote: | | Quote: | | so..... if you increase the translational component by the same amount you deacrease the rotational component (take wieght off the brake rotor and add it to the back of the seat) kinetic energy remains unchanged |
No!
The relationship between the two is not linear.
I think Joseph might need to explain this with some math... I "understand" the issue, but I can't easily give you the formula for the relationship. I'll leave that to someone that has a better education than I do.  |
Pete is correct. If you go back to the equations I provided, you'll
notice that the kinetic energy of a rotating body has two parts.
One is the rotational portion. The second is the translational component.
The translational component is the same 1/2 mvv that any component
moving in a straight line has. If you remove your brake rotor and
attach it to the back of your seat, the translational component (1/2
mvv) stays the same. But the rotational component disappears.
Moving your brake rotor from your axle to the back of your seat
will always make your kart faster. Just not enough to measure.
Those are the equations. They are hundreds of years old at this
point. I dare anyone to find any reputable source that contradicts
what I've said in any meaningful matter.
Seriously Scott, what's it gonna take? |
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William Marenich II
Joined: 20 Jan 2004 Posts: 122
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Posted: Mon Feb 23, 2004 12:31 am Post subject: |
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Acceleration of Gravity
At any distance r from a large circular body of mass M a smaller body of mass m will experience a gravitational force.

Applying Newton's Second (Fnet = ma) to the small object we can determine its acceleration if no other force are acting on the small mass m but gravity (Fnet = FG).
Acceleration of Gravity Near the Surface of a Large Body
Assume that a large body of mass M and radius R has a radically uniform mass distribution. The gravitational force on a small mass m at height h above the surface of the large body can be expressed as,

If h << R, then
If we neglect air resistance, then this is the net force acting on the mass m. Applying Newton's Second Law, Fnet = ma,
Because of its importance we usually give the acceleration of gravity due to the Earth a separate name,
* This equation does not depend upon the mass of the small object - the mass canceled out on both sides of the force equation. This proves that the acceleration due to gravity alone is the same on all objects independent of their mass, their size, their density, or even their speed. _________________ Danke,
William J. Marënich II |
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Mike Goebel
Joined: 28 Jul 2001 Posts: 5765 Location: United States, California, Winnetka
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Posted: Mon Feb 23, 2004 7:18 am Post subject: |
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Yeah gravity, that's a good one. Like that exists. Next you will be telling the superposition principle for a rolling and translating mass doesn't exits.
Mike G. |
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Scott McFadden
Joined: 20 Jul 2001 Posts: 125
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Posted: Mon Feb 23, 2004 8:09 am Post subject: |
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| joseph hollinger wrote: |
Seriously Scott, what's it gonna take? |
Ok Joseph we're get'n there. What I've been trying to reconcile since about half way through this thread is the difference between the "flywheel" analogies and the rotating parts of the kart that are in contact with the ground.
I agreed with Larry’s conclusions above, but your post, and specifically "the linear velocity of every particle ...is directed at right angles to the line joining P....the cylinder is rotating about a fixed axis through P with a certain angular speed..." crystallizes it. (for me anyway).
Now..... I was approached recently by a guy with a design for a perpetual motion machine that uses buoyancy as the motive force…
on second thoughts maybe I’ll save this ‘til next February. _________________ Scott |
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